1 cm on the main scale of a vernier callipers is divided into 10 equal parts. If 10 divisions of vernier coincide with 8 small divisions of main scale, then the least count of the calliper is

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0.01 cm

0.02 cm

0.05 cm

0.005 cm

answer is B.

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Detailed Solution

1MSD=110(1 cm)=1 mm10VSD=8MSD 1 VSD =810 MSD Least count =1MSD-1VSDLC=1 mm-810 mmLC=210 mmLC=2100 cm=0.02 cm

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