A coaxial cable consists of a thin inner conductor fixed along the axis of a hollow outer conductor. The two conductors carry equal currents in opposite directions. Let B1 and B2 be the magnetic fields in the region between the conductors and outside the conductor, respectively. Then,
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
B1 # 0, B2 # 0
b
B1=B2=0
c
B1 # 0, B2=0
d
B1 = 0, B2 # 0
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Apply Ampere's circuital law to the coaxial circular loops L1 and L2. The magnetic field is B1 at all points on L1 and B2 at all points on L,∑I≠0 for L1 and 0 for L2 Hence, B1≠0 but B2=0 As∮B→·dl→=μ0∑I