A coaxial cable consists of a thin inner conductor fixed along the axis of a hollow outer conductor. The two conductors carry equal currents in opposite directions. Let B1 and B2 be the magnetic fields in the region between the conductors, and outside the conductor, respectively. Then

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B1 ≠ B2 ≠0

B1=B2=0

B1 ≠ B2 =0

B1 = B2 ≠0

answer is C.

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Detailed Solution

Apply ampere's circuital law to the coaxial circular loops L1 and L2. The magnetic field is B1 at all points on L1 and B2 at all points on L2. ∑I ≠ 0 for L1 and 0 for L2.Hence B1 ≠0 but B2=0As ∮B→.dl→ = μ0 ∑I

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