The coefficient of apparent expansion of mercury in a glass vessel is 153 x 10- 6 /0C and in a steel vessel is 144 x 10- 6/°C. If α for steel is 12 x 10-6/°C, then that of glass is
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a
9 x 10-6/°C
b
6 x 10-6/°C
c
36 x 10-6/°C
d
27 x 10-6/°C
answer is C.
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Detailed Solution
We know thatγreal =γapparent +γvessel So,γapp +γvessel glass =γapp +γvessel steel ∵γreal is same in both cases) Or 153×10−6+γvessel glass =144×10−6+γvessel steel Further γvessel steel =3α=3×12×10−6=36×10−6/∘C∴ 153×10−6+γvessel glass =144×10−6+36×10−6Solving, we getγvessel glass =27×10−6/∘Cor α=γgalss 3=9×10−6/∘C