The coefficient of apparent expansion of mercury in a glass vessel is $$153$$ x $$10-$$ $$6$$ $$/0C$$ and in a steel vessel is $$144$$ x $$10-$$ $$6/$$°C. If α for steel is $$12$$ x $$10-6/$$°C, then that of glass is

Question

The coefficient of apparent expansion of mercury in a glass vessel is $$153$$ x $$10-$$ $$6$$ $$/0C$$  and in a steel vessel is $$144$$ x $$10-$$ $$6/$$°C. If α for steel is $$12$$ x $$10-6/$$°C, then that of glass is

Infinity Learn · Accepted Answer

We know thatγreal $$=$$γapparent $$+$$γvessel So,γapp $$+$$γvessel glass $$=$$γapp $$+$$γvessel steel ∵γreal  is same in both $$cases)$$ Or $$153$$×$$10$$−$$6+$$γvessel glass $$=144$$×$$10$$−$$6+$$γvessel steel  Further γvessel steel $$=3$$α$$=3$$×$$12$$×$$10$$−$$6=36$$×$$10$$−$$6/$$∘C∴ $$153$$×$$10$$−$$6+$$γvessel glass $$=144$$×$$10$$−$$6+36$$×$$10$$−$$6Solving$$, we getγvessel glass $$=27$$×$$10$$−$$6/$$∘Cor    α$$=$$γgalss $$3=9$$×$$10$$−$$6/$$∘C

The coefficient of apparent expansion of mercury in a glass vessel is 153 x 10^{- 6}/⁰C and in a steel vessel is 144 x 10^{- 6}/^°C. If $α$ for steel is 12 x 10^-6/°C, then that of glass is

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The coefficient of apparent expansion of mercury in a glass vessel is 153 x 10- 6 /0C and in a steel vessel is 144 x 10- 6/°C. If α for steel is 12 x 10-6/°C, then that of glass is

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The coefficient of apparent expansion of mercury in a glass vessel is 153 x 10^{- 6}/⁰C and in a steel vessel is 144 x 10^{- 6}/^°C. If $α$ for steel is 12 x 10^-6/°C, then that of glass is