First slide

Friction on horizontal surface

Question

The coefficient of friction between the 1.5 Kg block and the wall is 0.6. The block remains in equilibrium when a horizontal force of 30 N is applied on it. Then the frictional force acting on the block is

Easy

A

15 N
B

18 N
C

12 N
D

9 N

Solution

N = Normal reaction of wall = 30 N
$∴ f_{\max} = μ N = 0.6 \times 30 W = 18 N$
Weight of the block $= 1.5 \times 10 N = 15 N$
Since $f_{\max} > m g$ , frictional force acting on the block is 15 N.

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