The coefficient of friction between the 1.5 Kg block and the wall is 0.6. The block remains in equilibrium when a horizontal force of 30 N is applied on it. Then the frictional force acting on the block is

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15 N

18 N

12 N

9 N

answer is A.

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Detailed Solution

N = Normal reaction of wall = 30 N∴ fmax=μN=0.6×30 W=18 NWeight of the block =1.5×10N=15 NSince fmax>mg, frictional force acting on the block is 15 N.

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