The coefficient of friction between the two blocks is 0.3. whereas the surface AB is smooth.

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Acceleration of the system of masses is 88/15 ms−2.

Net force acting on 3 kg mass is greater than that on 2 kg mass.

Tension T2>T1

Since 10 kg mass is accelerating downwards, so the net force acting on it should be greater than any of the two blocks shown in figure.

answer is A.

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Detailed Solution

(1) Let the acceleration of each block be a. 10g−T2=10a, T2−T1−f=3a T1−f=2a, where f=0.3×2g=6 NFrom above equations 10g−2f=15a⇒10×10−2×6=15aa=88/15 ms−23 T2=10g−10a=10×10−10×8815=41.3N T1=f+2a=6+2×8815=17.7NClearly T2>T1(2) This is correct because of greater mass of 3 kg since acceleration is same for both. (4) This is incorrect, because net force acting on 10 kg mass is greater due to its larger mass, not due to its acceleration downward.

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