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The coefficient of linear expansion of brass and steel are α1 and α2. If we take a brass rod of length l1 and steel rod of length l2 at 0oC, their difference in length l2l1will remain the same at all temperatures if 

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By Expert Faculty of Sri Chaitanya
a
α1l2=α2l1
b
α1l22=α2l12
c
α12l1=α22l2
d
α1l1=α2l2
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detailed solution

Correct option is D

L2=l21+α2Δθ and L1=l11+α1Δθ⇒L2−L1=l2−l1+Δθl2α2−l1α1 Now L2−L1=l2−l1 so, l2α2−l1α1=0α1l1=l2α2


Similar Questions

A steel wire of cross sectional area 2mm2  is just stretched horizontally between two fixed points at a temperature of 350C . The temperature of the wire changed to 250C . Then (Coefficient of linear expansion of steel=11×106/0C;Ysteel=2×1011Nm2 )

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