Questions

The coefficient of linear expansion of brass and steel are $α_{1}$ and $α_{2}$ . If we take a brass rod of length $l_{1}$ and steel rod of length $l_{2}$ at 0^oC, their difference in length $(l_{2} - l_{1})$ will remain the same at all temperatures if

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α1l2=α2l1

α1l22=α2l12

α12l1=α22l2

α1l1=α2l2

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detailed solution

Correct option is D

L2=l21+α2Δθ and L1=l11+α1Δθ⇒L2−L1=l2−l1+Δθl2α2−l1α1 Now L2−L1=l2−l1 so, l2α2−l1α1=0α1l1=l2α2

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The coefficient of linear expansion of brass and steel are α1 and α2. If we take a brass rod of length l1 and steel rod of length l2 at 0oC, their difference in length l2−l1will remain the same at all temperatures if

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The coefficient of linear expansion of brass and steel are $α_{1}$ and $α_{2}$ . If we take a brass rod of length $l_{1}$ and steel rod of length $l_{2}$ at 0^oC, their difference in length $(l_{2} - l_{1})$ will remain the same at all temperatures if