Questions
The coefficient of mutual inductance of two circuits A and B is 3 mH and their respective resistances are 10 and 4 . How much current should change in 0.02 s in circuit A, so that the induced current in B should be 0.0060 A?
detailed solution
Correct option is D
Induced current in B=0.006A=6×10−3AInduced e.m.f. in B=iR=6×10−3×4V=24×10−3V Now, MdIdt=24×10−3 or dI=24×10−3×0.023×10−3A=0.16ATalk to our academic expert!
Similar Questions
Two conducting circular loops of radii R1 and R2 are placed in the same plane with their centers coinciding. If , the mutual inductance M between them will be directly proportional to
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
