First slide

Inductance

Question

The coefficient of mutual inductance of two circuits A and B is 3 mH and their respective resistances are 10 $Ω$ and 4 $Ω$ . How much current should change in 0.02 s in circuit A, so that the induced current in B should be 0.0060 A?

Moderate

A

0.24 A
B

1.6 A
C

0.18 A
D

0.16 A

Solution

Induced current in $B = 0.006 A = 6 \times 10^{- 3} A$
Induced e.m.f. in $B = i R = 6 \times 10^{- 3} \times 4 V = 24 \times 10^{- 3} V$
$\begin{array}{l} Now, M \frac{d I}{d t} = 24 \times 10^{- 3} \\ or d I = \frac{24 \times 10^{- 3} \times 0.02}{3 \times 10^{- 3}} A = 0.16 A \end{array}$

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