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The coefficient of mutual inductance of two circuits A and B is 3 mH and their respective resistances are 10Ω and 4 Ω. How much current should change in 0.02 s in circuit A, so that the induced current in B should be 0.0060 A?

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a

0.24 A

b

1.6 A

c

0.18 A

d

0.16 A

answer is D.

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Detailed Solution

Induced current in B=0.006A=6×10−3AInduced e.m.f. in B=iR=6×10−3×4V=24×10−3V Now, MdIdt=24×10−3 or dI=24×10−3×0.023×10−3A=0.16A

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The coefficient of mutual inductance of two circuits A and B is 3 mH and their respective resistances are 10Ω and 4 Ω. How much current should change in 0.02 s in circuit A, so that the induced current in B should be 0.0060 A?