The coefficient of mutual inductance of two circuits A and B is 3 mH and their respective resistances are 10Ω and 4Ω. How much current should change in 0.02 s in circuits, so that the induced current in B should be 0.0060 A?

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0.24 A

1.6 A

0.18 A

0.16 A

answer is D.

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Detailed Solution

Emf = 6×10-3×4=24×10-3VoltNow Mdidt=24×10-3⇒di=0.16 Amp

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