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Q.

The coefficient of self inductance of a solenoid is 0.18 mH. If a crode of soft iron of relative permeability 900 is inserted, then the coefficient of self inductance will become nearly

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a

5.4 mH

b

162 mH

c

0.006 mH

d

0.0002 mH

answer is B.

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Detailed Solution

L=μni⇒L2L1=μμ0=(n and i are same )⇒L2=μrL1=900×0.18=162mH
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