Q.
The coefficient of self-inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self-inductance will become nearly
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a
5.4 mH
b
162 mH
c
0.006 mH
d
0.0002 mH
answer is B.
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Detailed Solution
L∝μ⇒L2L1=μμ0 (n and i are same)⇒L2=μrL1=900×0.18=162mH
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