Download the app

Questions  

The coefficient of self-inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self-inductance will become nearly

a
5.4 mH
b
162 mH
c
0.006 mH
d
0.0002 mH

detailed solution

Correct option is B

L∝μ⇒L2L1=μμ0     (n and i are same)⇒L2=μrL1=900×0.18=162mH

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A coil is wound as a transformer of rectangular cross-section. If all the linear dimensions of the transformer are increased by a factor 2 and the number of turns per unit length of the coil remain the same, the self inductance increased by a factor of


phone icon
whats app icon