The coefficient of self-inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self-inductance will become nearly

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5.4 mH

162 mH

0.006 mH

0.0002 mH

answer is B.

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Detailed Solution

L∝μ⇒L2L1=μμ0 (n and i are same)⇒L2=μrL1=900×0.18=162mH

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