First slide

Inductance

Question

The coefficient of self-inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self-inductance will become nearly

Easy

A

5.4 mH
B

162 mH
C

0.006 mH
D

0.0002 mH

Solution

$L \propto μ \Rightarrow \frac{L_{2}}{L_{1}} = \frac{μ}{μ_{0}}$ (n and i are same)
$\Rightarrow L_{2} = μ_{r} L_{1} = 900 \times 0.18 = 162 mH$

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