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In a coil of area 10 cm2 and 10 turns, a magnetic field directed perpendicular to its plane and is changing at the rate of 108 gauss/second. The resistance of the coil is 20 ohm. The current in the coil will be

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a

5 A

b

0.5 A

c

0.05 A

d

5×108A

answer is A.

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Detailed Solution

I=|e|R=N(dϕ/dt)R=10×108×10−4×10−4×1020 Amp [104 Gauss = 1 Weber ] =5 A
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