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A coil of copper having 1O0O turns is placed in a magnetic field (B = 4x 10-3 T) perpendicular to its axis. The cross-sectional area of the coil is 0.05 m2. If it turns through 180o in 0.01 sec, then the e.m.f. induced in the coil is

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a

0.4 V

b

0.2 V

c

40 V

d

4 V

answer is C.

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Detailed Solution

The magnetic flux ϕ1 passing through a coil when it is placed perpendicular to magnetic field B isΦ=nBAWhen the coil is rotated through 90oΦ2=−nBA∴ΔΦ=Φ2−Φ1=−nBA−nBA=−2nBA Now e=−ΔΦΔt=+2nBAΔt=2×1000×4×10−3×0⋅050⋅01=40V

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