Q.

A coil has an inductance of 0.7 H and is joined in series with a resistance of 220Ω. When an alternating emf of 220 V at 50 cps is applied to it, then the wattless component of the current in the circuit is (take 0.7π=2.2)

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

5 A

b

0.5 A

c

0.7 A

d

7 A

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Wattless component of ac=Ivsinϕ=EvZXLZ=EvXLZ2=220×ωLR2+ω2L2As ωL=0.7×2π×50=220ΩHence, wattless component of ac=200×2202202+2202=0.5 A
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon