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Q.

A coil has an inductance of 0.7 H and is joined in series with a resistance of 220Ω. When an alternating emf of 220 V at 50 cps is applied to it, then the wattless component of the current in the circuit is (take 0.7π=2.2)

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a

5 A

b

0.5 A

c

0.7 A

d

7 A

answer is B.

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Detailed Solution

Wattless component of ac=Ivsinϕ=EvZXLZ=EvXLZ2=220×ωLR2+ω2L2As ωL=0.7×2π×50=220ΩHence, wattless component of ac=200×2202202+2202=0.5 A
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