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# A coil has an inductance of 0.7 H and is joined in series with a resistance of $220\Omega$. When an alternating emf of 220 V at 50 cps is applied to it, then the wattless component of the current in the circuit is (take $0.7\pi =2.2$)

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a
5 A
b
0.5 A
c
0.7 A
d
7 A

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detailed solution

Correct option is B

Wattless component of ac=Ivsinϕ=EvZXLZ=EvXLZ2=220×ωLR2+ω2L2As ωL=0.7×2π×50=220ΩHence, wattless component of ac=200×2202202+2202=0.5 A

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