A coil has an inductance of 0.7 H and is joined in series with a resistance of 220 Ω. When an AC e.m.f. of 220 V 50 Hz is applied to it, find the wattless component of current in the circuit is

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0.2 A

0.4 A

0.5 A

0.7 A

answer is C.

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Detailed Solution

XL=ωL=2πfL=220 Ωϕ=tan−1XLR=tan−1220220=45∘I=ER2+XL2=220(220)2+(220)2=12Wattless component of current =Isinϕ=12⋅sin45∘=0.5 A

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