Q.

A coil has resistance 30 ohm and inductive reactance 20 ohm at 50 Hz frequency. If an ac source, of 200 volt, 100 Hz, is connected across the coil, the current in the coil will be

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a

2.0 A

b

4.0 A

c

8.0 A

d

2013A

answer is B.

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Detailed Solution

Here, Resistance, R=30Ω  Inductive reactance, XL=20Ω at 50Hz ∵ XL=2πvL XL′=v′v×XL=10050×20Ω=40Ω  Impedance, Z=R2+XL′2=(30)2+(40)2=50Ω  Current in the coil, I=VZ=200V50Ω=4A
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