First slide

Magnetic flux and induced emf

Question

A coil has 1,000 turns and 500 cm² as its area. The plane of the coil is placed at right angles to a magnetic induction field of $2 \times 10^{- 5} Wb / m^{2}$ . The coil is rotated through 180^o in 0.2 seconds. The average e.m.f. induced in the coil, in milli-volts, is

Moderate

A

5
B

10
C

15
D

20

Solution

$\begin{array}{l} By using e = - \frac{NBA (\cos θ_{2} - \cos θ_{1})}{Δt} \\ e = - \frac{1000 \times 2 \times 10^{- 5} \times 500 \times 10^{- 4} (\cos 180^{\circ} - \cos 0^{\circ})}{0 .2} \\ = 10^{- 2} volt = 10 mV \end{array}$

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