A coil has 1000 turns and 500 cm2 as its area. The plane of the coil is placed at right angles to a magnetic induction field of 2×10−4 Wb/m2. The coil is rotated through 1800 in 0.2 s. The average e.m.f. induced in the coil, in millivolts, is

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answer is B.

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Detailed Solution

e=−NBAcosθ2−cosθ1Δte=−1000×2×10−4×500×10−4cos180∘−cos0∘0.2=10−2 volt =10 mV

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