Q.
For a coil having L = 2 mH, current flow through it is given by l=t2e-1, then the time at which emf becomes zero, is :
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a
2 s
b
1 s
c
4 s
d
3 s
answer is A.
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Detailed Solution
e=LdIdt=0⇒dIdt=0 dIdt=ddtt2e-t=2te-t+t2(-1)e-t=0 ⇒t=2 s
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