First slide

Phasors and Phasor Diagrams

Question

A coil of inductance 0.1 H is connected to 50 V 100 Hz generator and current is found to be 0.5 A. The potential difference across resistance of coil is

Moderate

A

15 V
B

20 V
C

25 V
D

39 V

Solution

$I = \frac{E}{Z} \Rightarrow 0 .5 = \frac{50}{Z} \Rightarrow Z = 100 Ω$
$Z^{2} = R^{2} + ω^{2} L^{2}, then R = 78 Ω$
Now, $V_{R} = \sqrt{V_{LR}^{2} - V_{L}^{2}} = 39 V$
$[∴ V_{R}^{2} + V_{L}^{2} = V_{LR}^{2}]$

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