Questions
A coil of inductance 300 mH and resistance is connected to a source of voltage 2V. The current reaches half of its steady state value in
detailed solution
Correct option is D
i = i01−e−RtL⇒ For i = i02,t =0.693LR⇒t=0.693×300×10−32=0.1 sTalk to our academic expert!
Similar Questions
In the circuit shown, one of the inductors used is ideal. The potential difference across the batteries is10 V. The current drawn from the battery at steady state, after the switch is closed is
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