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Q.

A coil of inductance 300 mH and resistance 2 Ω is connected to a source of voltage 2V. The current reaches half of its steady state value in

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a

0.15 s

b

0.3 s

c

0.05 s

d

0.1 s

answer is D.

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Detailed Solution

i = i01−e−RtL⇒ For i = i02,t =0.693LR⇒t=0.693×300×10−32=0.1 s
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