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A coil of inductance 8.4 mH and resistance is connected to a 12 V battery. The current in the coil is 1.0 A at approximately the time
detailed solution
Correct option is D
Peak current in the circuits, i0=126=2ACurrent decreases from 2 A to 1 A i.e., becomes half in time t=LRln 2=0.693×8.4×10−36=1 msTalk to our academic expert!
Similar Questions
In the circuit shown, one of the inductors used is ideal. The potential difference across the batteries is10 V. The current drawn from the battery at steady state, after the switch is closed is
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