First slide

Time -Varying current in L-R circuit

Question

A coil of inductance 8.4 mH and resistance $6 Ω$ is connected to a 12 V battery. The current in the coil is 1.0 A at approximately the time

Moderate

A

500 s
B

20 s
C

35 ms
D

1 ms

Solution

Peak current in the circuits, $i_{0} = \frac{12}{6} = 2 A$
Current decreases from 2 A to 1 A i.e., becomes half in time $t = \frac{L}{R} \ln 2 = 0 .693 \times \frac{8 .4 \times 10^{- 3}}{6} = 1 ms$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App