A coil of mean area 500 cm2 and 4000 turns is held perpendicular to a uniform field of 2 ´ 10-5 T. The coil is turned through 180° about its diameter in 0.1 sec. If resistance of the coil is 10 Ω, then the charge induced in the coil is (in μC)

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800

0.8

answer is B.

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Detailed Solution

Charge induced = ∆ϕR here∆ϕ is equal to 2NAB charge Q = 2×4000×500×10-4×2×10-510 =800×10-6 C

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