First slide

Phasors and Phasor Diagrams

Question

A coil of $200 Ω$ resistance and 1.0 H inductance is connected to an AC source of frequency $200 / 2 π Hz$ . Phase angle between potential and current will be

Easy

A

30⁰
B

90⁰
C

45⁰
D

0⁰

Solution

$tanϕ = \frac{X_{L}}{R} = \frac{2 πvL}{R} = \frac{2 π \times \frac{200}{2 π} \times 1}{200} = 1 \Rightarrow ϕ = 45^{\circ}$

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