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A coil of 40Ω resistance has 100 turns and radius 6 mm is connected to ammeter of resistance of 160 ohms. Coil is placed perpendicular to the magnetic field. When coil is taken out of the field, 32 μC charge flows through it. The intensity of magnetic field will be

a
6.55 T
b
5.66 T
c
0.655 T
d
0.566 T

detailed solution

Correct option is D

q=−NRB2−B1Acos⁡θ32×10−6=−100(160+40)(0−B)×π×6×10−32×cos⁡0∘⇒B=0.565T

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