Faraday's law of Electromagnetic induction

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Question

A coil of $40 Ω$ resistance having 100 turns and radius 6 mm is connected to an ammeter of resistance of 160 ohms. Coil is placed perpendicular to the magnetic field. When coil is taken out of the field, $32 μ C$ charge flows through it. The intensity of magnetic field will be

Moderate

Solution

$q = - \frac{N}{R} (B_{2} - B_{1}) A cosθ$
$\Rightarrow$ $32 \times 10^{- 6}$
$= - \frac{100}{(160 + 40)} (0 - B) \times π \times {(6 \times 10^{- 3})}^{2} \times \cos 0^{0}$
$\Rightarrow B = 0 .566 T$

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