First slide

Inductance

Question

A coil of resistance 10 $Ω$ and an inductance 5H is connected to a 100 volt battery. Then energy stored in the coil is

Moderate

A

125 erg
B

125 J
C

250 erg
D

250 J

Solution

$U= \frac{1}{2} {Li}^{2} \Rightarrow U = \frac{1}{2} \times 5 \times {(\frac{100}{10})}^{2} = 250 J$

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