First slide

Time -Varying current in L-R circuit

Question

A coil of self-inductance 50 henry is joined to the terminals of a battery of e.m.f. 2 volts through a resistance of 10 ohm and a steady current is flowing through the circuit. If the battery is now disconnected, the time in which the current will decay to 1/e of its steady value is

Moderate

A

500 seconds
B

50 seconds
C

5 seconds
D

0.5 seconds

Solution

Time in which the current will decay to $\frac{1}{e}$ of its steady value is $t = τ = \frac{L}{R} = \frac{50}{10} = 5 s$

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