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A coil of 100 turns and area 5 square centimeter is placed in a magnetic field B=0.2T. The normal to the plane of the coil makes an angle of 600 with the direction of the magnetic field. The magnetic flux linked with the coil is

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a

5×10−3Wb

b

5×10−5Wb

c

10−2Wb

d

10−4Wb

answer is A.

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Detailed Solution

N=100,A=5 cm2=5×10−4m2, B=0.2T θ=600 Magnetic Flux ϕ=NBA cosθ ϕ=100×0.2×5×10−4 cos60 =5×10−3Wb

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