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Questions  

A coil of 100 turns and area 5 square centimetre is placed in a magnetic field B = 0.2 T. The normal to the plane of the coil makes an angle of 60° with the direction of the magnetic field. The magnetic flux linked with the coil is

a
5×10−3Wb
b
5×10−5Wb
c
10−2Wb
d
10−4Wb

detailed solution

Correct option is A

ϕ=NBAcos⁡θ=100×0.2×5×10−4cos⁡60∘=5×10−3Wb

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