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A coil of wire of a certain radius has 600 turns and a self inductance of 108 mH. The self inductance of a 2nd similar coil of 500 turns will be
detailed solution
Correct option is B
LBLA=nBnA2⇒LB=5006002×108=75 mHTalk to our academic expert!
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Two conducting circular loops of radii R1 and R2 are placed in the same plane with their centers coinciding. If , the mutual inductance M between them will be directly proportional to
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