A coil with 1500 turns, a radius of 5.0 cm and a resistance of 12Ω surrounds a solenoid with 250 turns/cm and a radius of 4 cm; see figure. The current in the solenoid changes at a constant rate from 0 to 20 A in 0.10 s. The magnitude of the induced current (in A) in the 1500 turn coil is ( Take π2=10, Neglect self inductance of the coil)

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answer is 4.

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Detailed Solution

ε=1500×ddtμ0ni×π×4.01002=1500×4π×10−7×25010-2×200.1×π×4.0×4.0104i=εR=6000π2×5000×103×10−712×(4.0)2104i=4A

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