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Q.

The coils of a step down transformer have 500 and 5000 turns. In the primary coil an ac of 4 ampere at 2200 volts is sent. The value of the current and potential difference in the secondary coil will be

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a

20 A, 220 V

b

0.4 A, 22000 V

c

40 A, 220 V

d

40 A, 22000 V

answer is C.

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Detailed Solution

NpNs=VpVs=isip . The transformer is step-down type, so primary coil will have more turns. Hence 5000500=2200Vs=is4⇒Vs=220 V, is=40 amp

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