Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Column – I gives physical quantities of a situation in which a current i passes through two rods I and II of equal length that are joined in series. The ratio of free electron density (n), resistivity (ρ) and cross – section area (A) of both are in ratio n1:n2 =2 :1,  ρ1ρ2=2:1  and A1:A2=1:2 respectively. Column II gives corresponding results. Match the ratios in the column I with the values in column II

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

a – q, b – p, c – s, d – p

b

a – q, b – s, c – r, d – q

c

a – s, b – s, c – p, d – q

d

a – q, b – s, c – s, d – q

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

I=neAVd⇒Vd1Vd2=n2n1A2A1=1J=neVd=Eρ⇒E1E2=ρ1ρ2A2A1=4t=LVd⇒t1t2=Vd2Vd1=1V=EL⇒V1V2=E1E2=4
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring