Transistor

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Question

For a common emitter amplifier, the audio frequency voltage across the collector resistance 2 $kΩ$ is 2 V. If the current amplification factor of the transistor is 200, and the base resistance is 1.5 $kΩ$ , the input signal voltage and base current are

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Solution

collector current $I_{c} = \frac{V_{c}}{R_{c}} = \frac{2}{2 \times 10^{3}} = 10^{- 3} A$
$\begin{array}{rcl} current gain β & = & \frac{I_{c}}{I_{B}} \\ I_{B} & = & \frac{I_{c}}{β} = \frac{10^{- 3}}{200} = 0.5 \times 10^{- 5} = 5 μA \\ input votage is I_{B} R_{B} & = & 5 \times 10^{- 6} \times 1.5 \times 10^{3} = 7.5 \times 10^{- 3} V \end{array}$

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Transistor

Remember concepts with our Masterclasses.

For a common emitter amplifier, the audio frequency voltage across the collector resistance 2 kΩ is 2 V. If the current amplification factor of the transistor is 200, and the base resistance is 1.5 kΩ, the input signal voltage and base current are

collector current Ic=VcRc=22×103=10-3 A current gain β=IcIBIB=Icβ=10-3200=0.5×10-5=5 μAinput votage is IBRB=5×10-6×1.5×103=7.5×10-3 V

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For a common emitter amplifier, the audio frequency voltage across the collector resistance 2 $kΩ$ is 2 V. If the current amplification factor of the transistor is 200, and the base resistance is 1.5 $kΩ$ , the input signal voltage and base current are