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Q.

Common emitter amplifier circuit, built using an n – p – n transistor, is shown in the figure . Its DC current gain is 250, Rc=1kΩ  and Vcc=10V . What is the minimum base current for VCE to reach saturation.

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a

40μA

b

10μA

c

100μA

d

7μA

answer is A.

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Detailed Solution

For a common emitter n – p – n transistor, DC Current gain is     βDC=IcIB At saturation state VCE becomes zero     VCC−ICRC=0IC≈VCCRc=101000=10−2A  Hence , saturation base current    IB=IcβDC=10−2250=40μA
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