A common emitter amplifier circuit is shown in the figure below. For the transistor used in the circuit the current amplification factor, ${\beta }_{dc}=100$. Other parameters are mentioned in the figure.

We find that :

$\begin{array}{l}{\beta }_{dc}=100,{\beta }_{dc}=\frac{i_C}{i_B}\Rightarrow i_B=\frac{i_c}{100}----\left(1\right)\end{array}$

$\begin{array}{l}{V}_{CC}=+i_C{R}_L+V_{BC}+V_{BE}------\left(2\right)\\ -i_B{R}_B+V_{BC}+i_C{R}_L=0------\left(3\right)\\ Solvingweget V_{BE}=+20.7V,V_{BC}=-3.75V\end{array}$

NOTE: According to the question none of the options are matching. 4 th option is nearest.