A common emitter amplifier circuit is shown in the figure below. For the transistor used in the circuit the current amplification factor, $β_{d c} = 100$ . Other parameters are mentioned in the figure.
We find that :

Question

A common emitter amplifier circuit is shown in the figure below. For the transistor used in the circuit the current amplification factor, $β_{d c} = 100$ . Other parameters are mentioned in the figure.

We find that :

Infinity Learn · Accepted Answer

βdc  $$=$$  $$100$$,               β$$dc=iCiB$$  ⇒   $$iB=$$ $$ic100$$   −−−−(1)VCC$$ $$=$$  $$+iCRL$$  $$+$$ VBC  $$+$$  VBE       −−−−−−$$(2)−iBRB  $$+$$  VBC  $$+$$  $$iCRL=0$$        −−−−−−$$(3)Solving$$ we get   $$VBE=+20.7V$$,     $$VBC=$$−$$3.75VNOTE$$: According to the question none of the options are matching. $$4$$ th option is nearest.

Transistor

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A common emitter amplifier circuit is shown in the figure below. For the transistor used in the circuit the current amplification factor, $β_{d c} = 100$ . Other parameters are mentioned in the figure.
We find that :

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Transistor

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A common emitter amplifier circuit is shown in the figure below. For the transistor used in the circuit the current amplification factor, βdc=100. Other parameters are mentioned in the figure.We find that :

βdc = 100, βdc=iCiB ⇒ iB= ic100 −−−−(1)VCC = +iCRL + VBC + VBE −−−−−−(2)−iBRB + VBC + iCRL=0 −−−−−−(3)Solving we get VBE=+20.7V, VBC=−3.75VNOTE: According to the question none of the options are matching. 4 th option is nearest.

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A common emitter amplifier circuit is shown in the figure below. For the transistor used in the circuit the current amplification factor, $β_{d c} = 100$ . Other parameters are mentioned in the figure.
We find that :