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A common emitter amplifier is designed with NP transistor (a =0.99). The input impedance is 1k $Ω$ and load is 10 k $Ω$ . The voltage gain will be

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detailed solution

Correct option is C

Voltage gain = β x Resistance gainβ=α1-α=0.991-0.99=99 Resistance gain =10×103103=10 ⇒Voltage gain =99×10=990

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A common emitter amplifier is designed with NP transistor (a =0.99). The input impedance is 1kΩ and load is 10 kΩ. The voltage gain will be

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A common emitter amplifier is designed with NP transistor (a =0.99). The input impedance is 1k $Ω$ and load is 10 k $Ω$ . The voltage gain will be