Transistor

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Question

A common emitter amplifier is designed with npn transistor $(α = 0 .99)$ . The input impedance is $1 KΩ$ and load is $10 KΩ$ . The voltage gain will be

Moderate

Solution

Voltage gain = $β \times$ Resistance gain
$β = \frac{α}{1 - α} = \frac{0 .99}{1 - 0 .99} = 99$
Resistance gain = $\frac{10 \times 10^{3}}{10^{3}} = 10$
Voltage gain = $99 \times 10 = 990$

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