In a common emitter amplifier, using output resistance of $$5000$$ ohm and input resistance of $$2000$$ ohm, if the peak value of input signal voltage is $$10$$ mV and β $$=$$ $$50$$, then the peak value of output voltage is

Question

In a common emitter amplifier, using output resistance of $$5000$$ ohm and input resistance of $$2000$$ ohm, if the peak value of input signal voltage is $$10$$ mV and β $$=$$ $$50$$, then the peak value of output voltage is

Infinity Learn · Accepted Answer

In  common  emitter  mode,  the  transistor  is  current amplifier.∆$$IB=10$$×$$10-32000=5$$×$$10-6$$ A Again, β$$=$$∆IC∆IB or ∆$$IC=$$β×∆IB $$=50$$×$$5$$×$$10-6$$ $$A=250$$×$$10-6$$ A $$=2.5$$×$$10-4$$ A Peak value of output voltage $$=2.5$$×$$10-4$$×$$5000$$ $$volt=1.25$$ volt

In a common emitter amplifier, using output resistance of 5000 ohm and input resistance of 2000 ohm, if the peak value of input signal voltage is 10 mV and $β$ = 50, then the peak value of output voltage is

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In a common emitter amplifier, using output resistance of 5000 ohm and input resistance of 2000 ohm, if the peak value of input signal voltage is 10 mV and β = 50, then the peak value of output voltage is

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In a common emitter amplifier, using output resistance of 5000 ohm and input resistance of 2000 ohm, if the peak value of input signal voltage is 10 mV and $β$ = 50, then the peak value of output voltage is