Q.
In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 rnho and current gain 20, the voltage gain will be
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a
13G
b
54G
c
23G
d
1.5G
answer is C.
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Detailed Solution
Voltage gain= Current gain × Resistance gainAυ=β×RoutRin Transconductance, gm=βRin or Rin=βgm ∴ Aυ=gm Rout For first case, Aυ=G, gm=0.03mho, β=25 ∴ G=0.03Rout −−−(i) For second case, Aυ=G', gm=0.02mho,β=20 ∴ G'=0.02Rout −−−(ii) Divide (ii) by (i), we get G'G=23 or G'=23G
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