In the common emitter circuit shown in figure, if VBE=2 volt, VCE=5v, β=100, Then base current IB is
0.2 mA
0.1 mA
1 mA
0.5 mA
(2)
Here, 20−1.5 × 103 × IC−5=0⇒ IC=0.01 ANow, ICIB=β ⇒ IB=ICβ=0.01100 A=0.1 mA