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In the common emitter circuit shown in figure, if $V_{B E} = 2 v o l t, V_{C E} = 5 v, β = 100,$ Then base current $I_{B} i s$

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Correct option is B

(2)Here, 20−1.5 × 103 × IC−5=0⇒ IC=0.01 ANow, ICIB=β ⇒ IB=ICβ=0.01100 A=0.1 mA

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In the common emitter circuit shown in figure, if VBE=2 volt, VCE=5v, β=100, Then base current IB is

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In the common emitter circuit shown in figure, if $V_{B E} = 2 v o l t, V_{C E} = 5 v, β = 100,$ Then base current $I_{B} i s$