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In a common emitter transistor circuit, the base current is 40 $μA, then V_{BE} is$

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Correct option is B

Applying kirchoff 10−245×40×10−3=VBE

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In a common emitter transistor circuit, the base current is 40 μA,then VBE is

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In a common emitter transistor circuit, the base current is 40 $μA, then V_{BE} is$