Questions  

In a common emitter transistor circuit, the base current is 40 μA,then VBE is 

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a
2 V
b
0.2 V
c
0.8V
d
Zero
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detailed solution

Correct option is B

Applying kirchoff 10−245×40×10−3=VBE

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Similar Questions

In the circuit shown, the base current is 30 µA. The value of R1 is (Neglect VBE)

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