First slide

Transistor

Question

In a common-base mode of transistor, the collector current is 5 488 mA for an emitter current of 5 .60 mA. The value of the base current amplification factor (p) will be

Easy

A

49
B

50
C

51
D

48

Solution

$β= \frac{I_{C}}{I_{B}} and I_{E} = I_{C} + I_{B} ∴ β = \frac{I_{C}}{I_{E} - I_{C}} = \frac{5 \cdot 488}{5 \cdot 60 - 5 \cdot 488} = 49$

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