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Q.

In a common-emitter amplifier, using output resistance of 5000 ohm and input resistance of 2000 ohm, if the peak value of input signal voltages is 10 mV and β=50 , then the peak of output voltage is

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a

5×10−6V

b

2.5×10−4V

c

1.25 V

d

125 V

answer is C.

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Detailed Solution

ΔIB=10×10−32000=5×10−6A Asign, β=ΔICΔIB or ΔIC=β×ΔIB=50×5×10−6A=250×10−6A=2.5×10−4APeak value of output voltage =2.5×10−4×5000V=1.25V .

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