For a common-emitter configuration, if α and β have their usual meanings, the correct relationship between α and β is
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a
1α=1β+2
b
α=β1−β
c
α=β1+β
d
α=β21+β2
answer is C.
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Detailed Solution
As we know,In case of a common emitter configuration, DC current gain, α=ICIE.where, IC is collector current and IE is emitter current.AC current gain, β=ICIB ………..(i)where, lB is base current.Also, IE=IB+IC …….(ii)Dividing Eq. (i) by IC, we get⇒ IEIC=IBIC+1 [from Eq. (i)]⇒ 1α=1β+1⇒α=β1+β