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Q.

In a common-emitter transistor amplifier, signal voltage across the collector resistance of 2 kΩ is 2 volt. What should be the value of resistance RB in series with VBB voltage supply of 2 volt in the input circuit, if the DC base current is 10 times the signal current in RB ?(Given : Base emitter voltage, VBE = 0.6 voit; and current amplification factor β = 100 .

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a

7 kΩ

b

26 kΩ

c

10 kΩ

d

14 kΩ

answer is D.

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Detailed Solution

icAC=vmACRC=2 wolt 2kΩ=1mAiBAC=(i)ACβs=1mA100=0.01mAiBDC=10iBAC=0.1mA=10−4ARB=VIB=2−0.610−4=14kΩ
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