In communication system, only one percent frequency of signal of wavelength $$900$$ nm can be used as band width. How many channel of $$6MHz$$ band width can broadcast this? $$c=3$$×$$108m/s$$, $$h=6.6$$×$$10$$−$$34J$$−s

Question

In communication system, only one percent frequency of signal of wavelength $$900$$ nm can be used as band width. How many channel of $$6MHz$$ band width can broadcast this? $$c=3$$×$$108m/s$$, $$h=6.6$$×$$10$$−$$34J$$−s

Infinity Learn · Accepted Answer

Here signal wavelength, λ$$=900nm=9$$×$$10$$−$$7m$$  Frequency of source is  $$f=c$$λ$$=3$$×$$1089$$×$$10$$−$$7=3.33$$×$$1014Hz$$ ∴Total band width used for $$communication=$$ $$1$$ % of  $$3.33$$×$$1014Hz$$ $$=3.33$$×$$1012$$   So, number of channels for signals  $$=total$$ bandwidth available for communicationbandwidth of T.Vsignal                                                                       $$=3.33$$×$$10126$$×$$106=5.55$$×$$105$$

In communication system, only one percent frequency of signal of wavelength 900 nm can be used as band width. How many channel of 6MHz band width can broadcast this? $(c = 3 \times 10^{8} m / s, h = 6.6 \times 10^{- 34} J - s)$

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In communication system, only one percent frequency of signal of wavelength 900 nm can be used as band width. How many channel of 6MHz band width can broadcast this? c=3×108m/s, h=6.6×10−34J−s

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In communication system, only one percent frequency of signal of wavelength 900 nm can be used as band width. How many channel of 6MHz band width can broadcast this? $(c = 3 \times 10^{8} m / s, h = 6.6 \times 10^{- 34} J - s)$