Download the app

Questions  

Component of the vector A=2i^+3j^ along the vector B=(i^+j^)) is

a
52
b
42
c
23
d
None of these

detailed solution

Correct option is A

Component of A along B = A cos θ =  A·BB=2+31+1=52

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A vector 2i^+2j^ rotated about its tail through an angle 450 in clockwise direction. Then the new vector is


phone icon
whats app icon