Q.

The component of vector A→=2i^+3j^ along the vector B→=i^+j^ is

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a

52

b

102

c

52

d

5

answer is A.

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Detailed Solution

Acosθ=A→.B→B→=A→⋅B→|i→+j→|=(2i^+3j^).(i^+j^)2=2+32=52
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